A 50.0kg sprinter, starting from rest, runs 52.0m in 7.70 sec at constant acceleration.
What is the magnitude of the horizontal force acting on the sprinter?|||Use F = m x a
D = ut + 陆at虏 .. (u = 0)
a = 2D/t虏
a = 2*52 / 7.7虏 = 1.75 m/s虏
F = m*a = 50kg*1.75m/s虏 .. .. 鈻篎 = 87.7 N
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